Matematika Sekolah Menengah Atas plsss bantu jawab kak

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plsss bantu jawab kak

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Penjelasan dengan langkah-langkah:

[tex]BC = \sqrt{ {25}^{2} - {24}^{2} } \\ = \sqrt{625 - 576} \\ = \sqrt{49} \\ = 7 \: cm[/tex]

[tex] \sin(a) = \frac{bc}{ac} = \frac{7}{25} = \: 0,28 [/tex]

[tex] \cos(a) = \frac{ab}{ac} = \frac{24}{25} = 0,96[/tex]

[tex] \tan(a) = \frac{bc}{ab} = \frac{7}{24} = 0,29[/tex]

[tex] \sec(a) = \frac{ac}{ab} = \frac{25}{24} = 1,04[/tex]

[tex] \sin(c) = \frac{ab}{ac} = \frac{24}{25} = 0,96[/tex]

[tex] \cos(c) = \frac{bc}{ac} = \frac{7}{25} = 0,28[/tex]

[tex] \tan(c) = \frac{ab}{bc} = \frac{24}{7} = 3,43[/tex]

[tex] \cosec(c) = \frac{ac}{ab} = \frac{25}{24} = 1,04[/tex]

Semoga membantu ya...

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